Base | Representation |
---|---|
bin | 1011000001011111010001… |
… | …1010001000011101011001 |
3 | 1120220200100210200000201020 |
4 | 2300113310122020131121 |
5 | 3042034134011424423 |
6 | 41435540002313053 |
7 | 2360440635436203 |
oct | 260276432103531 |
9 | 46820323600636 |
10 | 12120203233113 |
11 | 395317082aa78 |
12 | 1438b87658789 |
13 | 69bc12a23a21 |
14 | 2dc899d09773 |
15 | 16041ab6d4e3 |
hex | b05f4688759 |
12120203233113 has 8 divisors (see below), whose sum is σ = 16162119802176. Its totient is φ = 8079211076400.
The previous prime is 12120203233037. The next prime is 12120203233121. The reversal of 12120203233113 is 31133230202121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12120203233113 - 29 = 12120203232601 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12120203233183) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 231072493 + ... + 231124938.
It is an arithmetic number, because the mean of its divisors is an integer number (2020264975272).
Almost surely, 212120203233113 is an apocalyptic number.
It is an amenable number.
12120203233113 is a deficient number, since it is larger than the sum of its proper divisors (4041916569063).
12120203233113 is an equidigital number, since it uses as much as digits as its factorization.
12120203233113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 462206175.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 12120203233113 its reverse (31133230202121), we get a palindrome (43253433435234).
The spelling of 12120203233113 in words is "twelve trillion, one hundred twenty billion, two hundred three million, two hundred thirty-three thousand, one hundred thirteen".
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