12120215030043 has 4 divisors (see below), whose sum is σ = 16160286706728. Its totient is φ = 8080143353360.

The previous prime is 12120215030041. The next prime is 12120215030087. The reversal of 12120215030043 is 34003051202121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12120215030043 - 2¹ = 12120215030041 is a prime.

It is a super-2 number, since 2×12120215030043² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12120215029995 and 12120215030022.

It is not an unprimeable number, because it can be changed into a prime (12120215030041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2020035838338 + ... + 2020035838343.

It is an arithmetic number, because the mean of its divisors is an integer number (4040071676682).

Almost surely, 2^{12120215030043} is an apocalyptic number.

12120215030043 is a deficient number, since it is larger than the sum of its proper divisors (4040071676685).

12120215030043 is an equidigital number, since it uses as much as digits as its factorization.

12120215030043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4040071676684.

The product of its (nonzero) digits is 1440, while the sum is 24.

Adding to 12120215030043 its reverse (34003051202121), we get a palindrome (46123266232164).

The spelling of 12120215030043 in words is "twelve trillion, one hundred twenty billion, two hundred fifteen million, thirty thousand, forty-three".