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1212032243993 is a prime number
BaseRepresentation
bin10001101000110010110…
…000000101100100011001
311021212110121111102202212
4101220302300011210121
5124324220223301433
62324444441204505
7153365201042414
oct21506260054431
94255417442685
101212032243993
1142802467109a
12176a97190735
138a3a932b9cc
144293c53ab7b
15217db1c9d48
hex11a32c05919

1212032243993 has 2 divisors, whose sum is σ = 1212032243994. Its totient is φ = 1212032243992.

The previous prime is 1212032243987. The next prime is 1212032244061. The reversal of 1212032243993 is 3993422302121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1178162626624 + 33869617369 = 1085432^2 + 184037^2 .

It is a cyclic number.

It is not a de Polignac number, because 1212032243993 - 24 = 1212032243977 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1212032243993.

It is not a weakly prime, because it can be changed into another prime (1212032243923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606016121996 + 606016121997.

It is an arithmetic number, because the mean of its divisors is an integer number (606016121997).

Almost surely, 21212032243993 is an apocalyptic number.

It is an amenable number.

1212032243993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1212032243993 is an equidigital number, since it uses as much as digits as its factorization.

1212032243993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 139968, while the sum is 41.

The spelling of 1212032243993 in words is "one trillion, two hundred twelve billion, thirty-two million, two hundred forty-three thousand, nine hundred ninety-three".