Base | Representation |
---|---|
bin | 10001101000110110110… |
… | …010100011100100101011 |
3 | 11021212122022222210121012 |
4 | 101220312302203210223 |
5 | 124324340100000133 |
6 | 2324455301334135 |
7 | 153366653002052 |
oct | 21506662434453 |
9 | 4255568883535 |
10 | 1212100000043 |
11 | 42805993a229 |
12 | 176ab5a0734b |
13 | 8a3ba39304a |
14 | 42947537399 |
15 | 217e2110b48 |
hex | 11a36ca392b |
1212100000043 has 2 divisors, whose sum is σ = 1212100000044. Its totient is φ = 1212100000042.
The previous prime is 1212100000039. The next prime is 1212100000063. The reversal of 1212100000043 is 3400000012121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1212100000043 - 22 = 1212100000039 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1212099999973 and 1212100000027.
It is not a weakly prime, because it can be changed into another prime (1212100000063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606050000021 + 606050000022.
It is an arithmetic number, because the mean of its divisors is an integer number (606050000022).
Almost surely, 21212100000043 is an apocalyptic number.
1212100000043 is a deficient number, since it is larger than the sum of its proper divisors (1).
1212100000043 is an equidigital number, since it uses as much as digits as its factorization.
1212100000043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 14.
Adding to 1212100000043 its reverse (3400000012121), we get a palindrome (4612100012164).
The spelling of 1212100000043 in words is "one trillion, two hundred twelve billion, one hundred million, forty-three", and thus it is an aban number.
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