Base | Representation |
---|---|
bin | 11011100011110101101110… |
… | …001001110010011011110011 |
3 | 120220011120111200021111210001 |
4 | 123203311232021302123303 |
5 | 111341401311222320201 |
6 | 1105443054354450431 |
7 | 34350066525403324 |
oct | 3343655611623363 |
9 | 526146450244701 |
10 | 121210120120051 |
11 | 35691a17959286 |
12 | 117173bbb93a17 |
13 | 52830b056b5a1 |
14 | 21d085b66844b |
15 | e02e47a2a301 |
hex | 6e3d6e2726f3 |
121210120120051 has 2 divisors, whose sum is σ = 121210120120052. Its totient is φ = 121210120120050.
The previous prime is 121210120119967. The next prime is 121210120120127. The reversal of 121210120120051 is 150021021012121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121210120120051 - 27 = 121210120119923 is a prime.
It is not a weakly prime, because it can be changed into another prime (121210120130051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60605060060025 + 60605060060026.
It is an arithmetic number, because the mean of its divisors is an integer number (60605060060026).
Almost surely, 2121210120120051 is an apocalyptic number.
121210120120051 is a deficient number, since it is larger than the sum of its proper divisors (1).
121210120120051 is an equidigital number, since it uses as much as digits as its factorization.
121210120120051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 19.
Adding to 121210120120051 its reverse (150021021012121), we get a palindrome (271231141132172).
The spelling of 121210120120051 in words is "one hundred twenty-one trillion, two hundred ten billion, one hundred twenty million, one hundred twenty thousand, fifty-one".
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