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1212120011969 is a prime number
BaseRepresentation
bin10001101000110111111…
…110111001010011000001
311021212200201122111210122
4101220313332321103001
5124324410210340334
62324501254310025
7153400315050626
oct21506776712301
94255621574718
101212120011969
1142806a168509
12176b00658315
138a3c157ba19
144294a06634d
15217e3c6532e
hex11a37fb94c1

1212120011969 has 2 divisors, whose sum is σ = 1212120011970. Its totient is φ = 1212120011968.

The previous prime is 1212120011917. The next prime is 1212120012007. The reversal of 1212120011969 is 9691100212121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 610429690000 + 601690321969 = 781300^2 + 775687^2 .

It is an emirp because it is prime and its reverse (9691100212121) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1212120011969 is a prime.

It is a super-2 number, since 2×12121200119692 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1212120019969) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606060005984 + 606060005985.

It is an arithmetic number, because the mean of its divisors is an integer number (606060005985).

Almost surely, 21212120011969 is an apocalyptic number.

It is an amenable number.

1212120011969 is a deficient number, since it is larger than the sum of its proper divisors (1).

1212120011969 is an equidigital number, since it uses as much as digits as its factorization.

1212120011969 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 35.

The spelling of 1212120011969 in words is "one trillion, two hundred twelve billion, one hundred twenty million, eleven thousand, nine hundred sixty-nine".