Base | Representation |
---|---|
bin | 10001101000111000000… |
… | …110011110101011110001 |
3 | 11021212200212101112000121 |
4 | 101220320012132223301 |
5 | 124324411213000423 |
6 | 2324501405050241 |
7 | 153400341001153 |
oct | 21507006365361 |
9 | 4255625345017 |
10 | 1212122000113 |
11 | 4280702a6202 |
12 | 176b01256981 |
13 | 8a3c1ac693b |
14 | 4294a422ad3 |
15 | 217e400945d |
hex | 11a3819eaf1 |
1212122000113 has 2 divisors, whose sum is σ = 1212122000114. Its totient is φ = 1212122000112.
The previous prime is 1212122000099. The next prime is 1212122000123. The reversal of 1212122000113 is 3110002212121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1212007231744 + 114768369 = 1100912^2 + 10713^2 .
It is a cyclic number.
It is not a de Polignac number, because 1212122000113 - 225 = 1212088445681 is a prime.
It is not a weakly prime, because it can be changed into another prime (1212122000123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606061000056 + 606061000057.
It is an arithmetic number, because the mean of its divisors is an integer number (606061000057).
Almost surely, 21212122000113 is an apocalyptic number.
It is an amenable number.
1212122000113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1212122000113 is an equidigital number, since it uses as much as digits as its factorization.
1212122000113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 1212122000113 its reverse (3110002212121), we get a palindrome (4322124212234).
The spelling of 1212122000113 in words is "one trillion, two hundred twelve billion, one hundred twenty-two million, one hundred thirteen", and thus it is an aban number.
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