Base | Representation |
---|---|
bin | 1011000001100101010110… |
… | …0010010011010101001011 |
3 | 1120220211120100220210212201 |
4 | 2300121111202103111023 |
5 | 3042101003141432442 |
6 | 41440405413021031 |
7 | 2360526213304246 |
oct | 260312542232513 |
9 | 46824510823781 |
10 | 12121832764747 |
11 | 3953927642232 |
12 | 1439361324777 |
13 | 69c1124c9524 |
14 | 2dc9b24ca25d |
15 | 1604b3c527b7 |
hex | b065589354b |
12121832764747 has 2 divisors, whose sum is σ = 12121832764748. Its totient is φ = 12121832764746.
The previous prime is 12121832764733. The next prime is 12121832764751. The reversal of 12121832764747 is 74746723812121.
It is a strong prime.
It is an emirp because it is prime and its reverse (74746723812121) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12121832764747 is a prime.
It is not a weakly prime, because it can be changed into another prime (12121832762747) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060916382373 + 6060916382374.
It is an arithmetic number, because the mean of its divisors is an integer number (6060916382374).
Almost surely, 212121832764747 is an apocalyptic number.
12121832764747 is a deficient number, since it is larger than the sum of its proper divisors (1).
12121832764747 is an equidigital number, since it uses as much as digits as its factorization.
12121832764747 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6322176, while the sum is 55.
The spelling of 12121832764747 in words is "twelve trillion, one hundred twenty-one billion, eight hundred thirty-two million, seven hundred sixty-four thousand, seven hundred forty-seven".
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