Base | Representation |
---|---|
bin | 10110100101000011… |
… | …10011100110001001 |
3 | 1011021210201000101221 |
4 | 23102201303212021 |
5 | 144311213341131 |
6 | 5322504442041 |
7 | 606252254656 |
oct | 132241634611 |
9 | 34253630357 |
10 | 12122012041 |
11 | 5160618077 |
12 | 2423779321 |
13 | 11b25144b9 |
14 | 82dcdcc2d |
15 | 4ae322411 |
hex | 2d2873989 |
12122012041 has 2 divisors, whose sum is σ = 12122012042. Its totient is φ = 12122012040.
The previous prime is 12122012009. The next prime is 12122012047. The reversal of 12122012041 is 14021022121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6544162816 + 5577849225 = 80896^2 + 74685^2 .
It is an emirp because it is prime and its reverse (14021022121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12122012041 - 25 = 12122012009 is a prime.
It is not a weakly prime, because it can be changed into another prime (12122012047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6061006020 + 6061006021.
It is an arithmetic number, because the mean of its divisors is an integer number (6061006021).
Almost surely, 212122012041 is an apocalyptic number.
It is an amenable number.
12122012041 is a deficient number, since it is larger than the sum of its proper divisors (1).
12122012041 is an equidigital number, since it uses as much as digits as its factorization.
12122012041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 16.
Adding to 12122012041 its reverse (14021022121), we get a palindrome (26143034162).
The spelling of 12122012041 in words is "twelve billion, one hundred twenty-two million, twelve thousand, forty-one".
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