Search a number
-
+
121220302312033 is a prime number
BaseRepresentation
bin11011100011111111001101…
…000011110001001001100001
3120220012112210021212110022121
4123203333031003301021201
5111342033134342441113
61105451501010304241
734350610044533251
oct3343771503611141
9526175707773277
10121220302312033
11356962724a2881
1211719381b88081
135284043c19562
1421d1145a95961
15e033418c5e8d
hex6e3fcd0f1261

121220302312033 has 2 divisors, whose sum is σ = 121220302312034. Its totient is φ = 121220302312032.

The previous prime is 121220302311989. The next prime is 121220302312049. The reversal of 121220302312033 is 330213203022121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111387612565089 + 9832689746944 = 10554033^2 + 3135712^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121220302312033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 121220302311989 and 121220302312007.

It is not a weakly prime, because it can be changed into another prime (121220302312063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60610151156016 + 60610151156017.

It is an arithmetic number, because the mean of its divisors is an integer number (60610151156017).

Almost surely, 2121220302312033 is an apocalyptic number.

It is an amenable number.

121220302312033 is a deficient number, since it is larger than the sum of its proper divisors (1).

121220302312033 is an equidigital number, since it uses as much as digits as its factorization.

121220302312033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 121220302312033 its reverse (330213203022121), we get a palindrome (451433505334154).

The spelling of 121220302312033 in words is "one hundred twenty-one trillion, two hundred twenty billion, three hundred two million, three hundred twelve thousand, thirty-three".