Base | Representation |
---|---|
bin | 1011000001100110010110… |
… | …0001100111101000111011 |
3 | 1120220212021001200122121111 |
4 | 2300121211201213220323 |
5 | 3042102030330134433 |
6 | 41440452154421151 |
7 | 2360535651404203 |
oct | 260314541475073 |
9 | 46825231618544 |
10 | 12122101021243 |
11 | 3953a55005314 |
12 | 14394171317b7 |
13 | 69c155c61895 |
14 | 2dc9d9d99403 |
15 | 1604cc590dcd |
hex | b0665867a3b |
12122101021243 has 2 divisors, whose sum is σ = 12122101021244. Its totient is φ = 12122101021242.
The previous prime is 12122101021207. The next prime is 12122101021333. The reversal of 12122101021243 is 34212010122121.
12122101021243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12122101021243 is a prime.
It is not a weakly prime, because it can be changed into another prime (12122101021543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6061050510621 + 6061050510622.
It is an arithmetic number, because the mean of its divisors is an integer number (6061050510622).
Almost surely, 212122101021243 is an apocalyptic number.
12122101021243 is a deficient number, since it is larger than the sum of its proper divisors (1).
12122101021243 is an equidigital number, since it uses as much as digits as its factorization.
12122101021243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 12122101021243 its reverse (34212010122121), we get a palindrome (46334111143364).
The spelling of 12122101021243 in words is "twelve trillion, one hundred twenty-two billion, one hundred one million, twenty-one thousand, two hundred forty-three".
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