Base | Representation |
---|---|
bin | 1011000001100110010110… |
… | …0001100111101011100011 |
3 | 1120220212021001200122211201 |
4 | 2300121211201213223203 |
5 | 3042102030330141121 |
6 | 41440452154422031 |
7 | 2360535651404533 |
oct | 260314541475343 |
9 | 46825231618751 |
10 | 12122101021411 |
11 | 3953a55005457 |
12 | 1439417131917 |
13 | 69c155c61994 |
14 | 2dc9d9d994c3 |
15 | 1604cc590e91 |
hex | b0665867ae3 |
12122101021411 has 2 divisors, whose sum is σ = 12122101021412. Its totient is φ = 12122101021410.
The previous prime is 12122101021399. The next prime is 12122101021421. The reversal of 12122101021411 is 11412010122121.
12122101021411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12122101021411 - 29 = 12122101020899 is a prime.
It is not a weakly prime, because it can be changed into another prime (12122101021421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6061050510705 + 6061050510706.
It is an arithmetic number, because the mean of its divisors is an integer number (6061050510706).
Almost surely, 212122101021411 is an apocalyptic number.
12122101021411 is a deficient number, since it is larger than the sum of its proper divisors (1).
12122101021411 is an equidigital number, since it uses as much as digits as its factorization.
12122101021411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 19.
Adding to 12122101021411 its reverse (11412010122121), we get a palindrome (23534111143532).
The spelling of 12122101021411 in words is "twelve trillion, one hundred twenty-two billion, one hundred one million, twenty-one thousand, four hundred eleven".
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