Base | Representation |
---|---|
bin | 1011000001100110010110… |
… | …0101101111100001100001 |
3 | 1120220212021010201120021201 |
4 | 2300121211211233201201 |
5 | 3042102031114231423 |
6 | 41440452233521201 |
7 | 2360535663525343 |
oct | 260314545574141 |
9 | 46825233646251 |
10 | 12122102102113 |
11 | 3953a556833a3 |
12 | 1439417573201 |
13 | 69c15624c853 |
14 | 2dc9da19b293 |
15 | 1604cc7062ad |
hex | b066596f861 |
12122102102113 has 4 divisors (see below), whose sum is σ = 12239792413888. Its totient is φ = 12004411790340.
The previous prime is 12122102102107. The next prime is 12122102102137. The reversal of 12122102102113 is 31120120122121.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12122102102113 - 217 = 12122101971041 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12122102102183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58845155733 + ... + 58845155938.
It is an arithmetic number, because the mean of its divisors is an integer number (3059948103472).
Almost surely, 212122102102113 is an apocalyptic number.
It is an amenable number.
12122102102113 is a deficient number, since it is larger than the sum of its proper divisors (117690311775).
12122102102113 is a wasteful number, since it uses less digits than its factorization.
12122102102113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 117690311774.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 12122102102113 its reverse (31120120122121), we get a palindrome (43242222224234).
The spelling of 12122102102113 in words is "twelve trillion, one hundred twenty-two billion, one hundred two million, one hundred two thousand, one hundred thirteen".
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