1212211214433 has 12 divisors (see below), whose sum is σ = 1780649242320. Its totient is φ = 794443507416.

The previous prime is 1212211214393. The next prime is 1212211214479. The reversal of 1212211214433 is 3344121122121.

1212211214433 is a `hidden beast` number, since 1 + 2 + 1 + 2 + 2 + 11 + 214 + 433 = 666.

It is not a de Polignac number, because 1212211214433 - 2³⁶ = 1143491737697 is a prime.

It is a super-2 number, since 2×1212211214433² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1212211214397 and 1212211214406.

It is not an unprimeable number, because it can be changed into a prime (1212211210433) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1141441291 + ... + 1141442352.

It is an arithmetic number, because the mean of its divisors is an integer number (148387436860).

Almost surely, 2^{1212211214433} is an apocalyptic number.

It is an amenable number.

1212211214433 is a deficient number, since it is larger than the sum of its proper divisors (568438027887).

1212211214433 is a wasteful number, since it uses less digits than its factorization.

1212211214433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2282883708 (or 2282883705 counting only the distinct ones).

The product of its digits is 2304, while the sum is 27.

Adding to 1212211214433 its reverse (3344121122121), we get a palindrome (4556332336554).

The spelling of 1212211214433 in words is "one trillion, two hundred twelve billion, two hundred eleven million, two hundred fourteen thousand, four hundred thirty-three".