12122213131 has 4 divisors (see below), whose sum is σ = 13853957872. Its totient is φ = 10390468392.

The previous prime is 12122213111. The next prime is 12122213141. The reversal of 12122213131 is 13131222121.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13131222121 = 2089 ⋅6285889.

It is a cyclic number.

It is not a de Polignac number, because 12122213131 - 2⁵ = 12122213099 is a prime.

It is a super-3 number, since 3×12122213131³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12122213099 and 12122213108.

It is not an unprimeable number, because it can be changed into a prime (12122213111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 865872360 + ... + 865872373.

It is an arithmetic number, because the mean of its divisors is an integer number (3463489468).

Almost surely, 2^12122213131 is an apocalyptic number.

12122213131 is a deficient number, since it is larger than the sum of its proper divisors (1731744741).

12122213131 is an equidigital number, since it uses as much as digits as its factorization.

12122213131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1731744740.

The product of its digits is 144, while the sum is 19.

Adding to 12122213131 its reverse (13131222121), we get a palindrome (25253435252).

The spelling of 12122213131 in words is "twelve billion, one hundred twenty-two million, two hundred thirteen thousand, one hundred thirty-one".