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12123014833697 is a prime number
BaseRepresentation
bin1011000001101001101111…
…1111100010011000100001
31120220221121202012010122012
42300122123333202120201
53042110413244134242
641441123000522305
72360600415601355
oct260323377423041
946827552163565
1012123014833697
113954383911119
121439631180395
1369c270383201
142dca854ad465
151605328ea282
hexb069bfe2621

12123014833697 has 2 divisors, whose sum is σ = 12123014833698. Its totient is φ = 12123014833696.

The previous prime is 12123014833667. The next prime is 12123014833711. The reversal of 12123014833697 is 79633841032121.

12123014833697 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11990769147361 + 132245686336 = 3462769^2 + 363656^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12123014833697 is a prime.

It is not a weakly prime, because it can be changed into another prime (12123014833667) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6061507416848 + 6061507416849.

It is an arithmetic number, because the mean of its divisors is an integer number (6061507416849).

Almost surely, 212123014833697 is an apocalyptic number.

It is an amenable number.

12123014833697 is a deficient number, since it is larger than the sum of its proper divisors (1).

12123014833697 is an equidigital number, since it uses as much as digits as its factorization.

12123014833697 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1306368, while the sum is 50.

The spelling of 12123014833697 in words is "twelve trillion, one hundred twenty-three billion, fourteen million, eight hundred thirty-three thousand, six hundred ninety-seven".