12123243202033 has 4 divisors (see below), whose sum is σ = 12240944592448. Its totient is φ = 12005541811620.

The previous prime is 12123243201997. The next prime is 12123243202039. The reversal of 12123243202033 is 33020234232121.

12123243202033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12123243202033 - 2⁴¹ = 9924219946481 is a prime.

It is a super-3 number, since 3×12123243202033³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12123243201992 and 12123243202010.

It is not an unprimeable number, because it can be changed into a prime (12123243202039) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58850695053 + ... + 58850695258.

It is an arithmetic number, because the mean of its divisors is an integer number (3060236148112).

Almost surely, 2^{12123243202033} is an apocalyptic number.

It is an amenable number.

12123243202033 is a deficient number, since it is larger than the sum of its proper divisors (117701390415).

12123243202033 is a wasteful number, since it uses less digits than its factorization.

12123243202033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 117701390414.

The product of its (nonzero) digits is 10368, while the sum is 28.

Adding to 12123243202033 its reverse (33020234232121), we get a palindrome (45143477434154).

The spelling of 12123243202033 in words is "twelve trillion, one hundred twenty-three billion, two hundred forty-three million, two hundred two thousand, thirty-three".