Base | Representation |
---|---|
bin | 1011000001101101110011… |
… | …1011010001010000010001 |
3 | 1120221001102200002101220121 |
4 | 2300123130323101100101 |
5 | 3042120131140442001 |
6 | 41441423034310241 |
7 | 2360636414416504 |
oct | 260333473212021 |
9 | 46831380071817 |
10 | 12124104234001 |
11 | 3954892846751 |
12 | 1439895b88381 |
13 | 69c3b4c92386 |
14 | 2dcb4a04d13b |
15 | 16059838a6a1 |
hex | b06dced1411 |
12124104234001 has 2 divisors, whose sum is σ = 12124104234002. Its totient is φ = 12124104234000.
The previous prime is 12124104233993. The next prime is 12124104234013. The reversal of 12124104234001 is 10043240142121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12122931240000 + 1172994001 = 3481800^2 + 34249^2 .
It is a cyclic number.
It is not a de Polignac number, because 12124104234001 - 23 = 12124104233993 is a prime.
It is not a weakly prime, because it can be changed into another prime (12124104234041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6062052117000 + 6062052117001.
It is an arithmetic number, because the mean of its divisors is an integer number (6062052117001).
Almost surely, 212124104234001 is an apocalyptic number.
It is an amenable number.
12124104234001 is a deficient number, since it is larger than the sum of its proper divisors (1).
12124104234001 is an equidigital number, since it uses as much as digits as its factorization.
12124104234001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 12124104234001 its reverse (10043240142121), we get a palindrome (22167344376122).
The spelling of 12124104234001 in words is "twelve trillion, one hundred twenty-four billion, one hundred four million, two hundred thirty-four thousand, one".
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