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12130011307 is a prime number
BaseRepresentation
bin10110100110000000…
…10100100010101011
31011022100202102100001
423103000110202223
5144320240330212
65323352123431
7606410252311
oct132300244253
934270672301
1012130011307
115165091037
122426396577
1311b40854ab
14830dc20b1
154aeda2657
hex2d30148ab

12130011307 has 2 divisors, whose sum is σ = 12130011308. Its totient is φ = 12130011306.

The previous prime is 12130011269. The next prime is 12130011323. The reversal of 12130011307 is 70311003121.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12130011307 is a prime.

It is not a weakly prime, because it can be changed into another prime (12130011107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6065005653 + 6065005654.

It is an arithmetic number, because the mean of its divisors is an integer number (6065005654).

Almost surely, 212130011307 is an apocalyptic number.

12130011307 is a deficient number, since it is larger than the sum of its proper divisors (1).

12130011307 is an equidigital number, since it uses as much as digits as its factorization.

12130011307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 126, while the sum is 19.

Adding to 12130011307 its reverse (70311003121), we get a palindrome (82441014428).

The spelling of 12130011307 in words is "twelve billion, one hundred thirty million, eleven thousand, three hundred seven".