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1213003031001 = 3666436067169
BaseRepresentation
bin10001101001101100100…
…111010110000111011001
311021221222021012112012020
4101221230213112013121
5124333212233443001
62325125040405053
7153431226433266
oct21515447260731
94257867175166
101213003031001
11428482651803
12177108316789
138a5024ab1a8
14429d144226d
152184653a736
hex11a6c9d61d9

1213003031001 has 8 divisors (see below), whose sum is σ = 1617361909920. Its totient is φ = 808656419712.

The previous prime is 1213003030979. The next prime is 1213003031059. The reversal of 1213003031001 is 1001303003121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1213003031001 - 211 = 1213003028953 is a prime.

It is a super-2 number, since 2×12130030310012 (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1213003033001) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2833656 + ... + 3233513.

It is an arithmetic number, because the mean of its divisors is an integer number (202170238740).

Almost surely, 21213003031001 is an apocalyptic number.

It is an amenable number.

1213003031001 is a deficient number, since it is larger than the sum of its proper divisors (404358878919).

1213003031001 is an equidigital number, since it uses as much as digits as its factorization.

1213003031001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6133815.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 1213003031001 its reverse (1001303003121), we get a palindrome (2214306034122).

The spelling of 1213003031001 in words is "one trillion, two hundred thirteen billion, three million, thirty-one thousand, one".

Divisors: 1 3 66643 199929 6067169 18201507 404334343667 1213003031001