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1213010433 = 32173779069
BaseRepresentation
bin100100001001101…
…0001001000000001
310010112111022111100
41020103101020001
54441012313213
6320211005013
742026263365
oct11023211001
93115438440
101213010433
11572792768
1229a299769
131643cb36b
14b71592a5
157175a773
hex484d1201

1213010433 has 12 divisors (see below), whose sum is σ = 1762256340. Its totient is φ = 803998176.

The previous prime is 1213010371. The next prime is 1213010453. The reversal of 1213010433 is 3340103121.

It can be written as a sum of positive squares in 2 ways, for example, as 853983729 + 359026704 = 29223^2 + 18948^2 .

It is not a de Polignac number, because 1213010433 - 29 = 1213009921 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1213010453) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 387978 + ... + 391091.

It is an arithmetic number, because the mean of its divisors is an integer number (146854695).

Almost surely, 21213010433 is an apocalyptic number.

It is an amenable number.

1213010433 is a deficient number, since it is larger than the sum of its proper divisors (549245907).

1213010433 is a wasteful number, since it uses less digits than its factorization.

1213010433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 779248 (or 779245 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

The square root of 1213010433 is about 34828.2993124844. The cubic root of 1213010433 is about 1066.4852305442.

Adding to 1213010433 its reverse (3340103121), we get a palindrome (4553113554).

The spelling of 1213010433 in words is "one billion, two hundred thirteen million, ten thousand, four hundred thirty-three".

Divisors: 1 3 9 173 519 1557 779069 2337207 7011621 134778937 404336811 1213010433