Base | Representation |
---|---|
bin | 1011000010000101000000… |
… | …1001111101100010000001 |
3 | 1120221122111201112200002120 |
4 | 2300201100021331202001 |
5 | 3042220410100320023 |
6 | 41444333042234453 |
7 | 2361246642265611 |
oct | 260412011754201 |
9 | 46848451480076 |
10 | 12130332432513 |
11 | 395749946a449 |
12 | 143ab33955a29 |
13 | 69cb68409439 |
14 | 2dd17b2a0a41 |
15 | 16081004c8e3 |
hex | b085027d881 |
12130332432513 has 4 divisors (see below), whose sum is σ = 16173776576688. Its totient is φ = 8086888288340.
The previous prime is 12130332432509. The next prime is 12130332432521. The reversal of 12130332432513 is 31523423303121.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12130332432513 - 22 = 12130332432509 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12130332432583) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2021722072083 + ... + 2021722072088.
It is an arithmetic number, because the mean of its divisors is an integer number (4043444144172).
Almost surely, 212130332432513 is an apocalyptic number.
It is an amenable number.
12130332432513 is a deficient number, since it is larger than the sum of its proper divisors (4043444144175).
12130332432513 is an equidigital number, since it uses as much as digits as its factorization.
12130332432513 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4043444144174.
The product of its (nonzero) digits is 38880, while the sum is 33.
Adding to 12130332432513 its reverse (31523423303121), we get a palindrome (43653755735634).
The spelling of 12130332432513 in words is "twelve trillion, one hundred thirty billion, three hundred thirty-two million, four hundred thirty-two thousand, five hundred thirteen".
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