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12130332432513 = 34043444144171
BaseRepresentation
bin1011000010000101000000…
…1001111101100010000001
31120221122111201112200002120
42300201100021331202001
53042220410100320023
641444333042234453
72361246642265611
oct260412011754201
946848451480076
1012130332432513
11395749946a449
12143ab33955a29
1369cb68409439
142dd17b2a0a41
1516081004c8e3
hexb085027d881

12130332432513 has 4 divisors (see below), whose sum is σ = 16173776576688. Its totient is φ = 8086888288340.

The previous prime is 12130332432509. The next prime is 12130332432521. The reversal of 12130332432513 is 31523423303121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12130332432513 - 22 = 12130332432509 is a prime.

It is not an unprimeable number, because it can be changed into a prime (12130332432583) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2021722072083 + ... + 2021722072088.

It is an arithmetic number, because the mean of its divisors is an integer number (4043444144172).

Almost surely, 212130332432513 is an apocalyptic number.

It is an amenable number.

12130332432513 is a deficient number, since it is larger than the sum of its proper divisors (4043444144175).

12130332432513 is an equidigital number, since it uses as much as digits as its factorization.

12130332432513 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4043444144174.

The product of its (nonzero) digits is 38880, while the sum is 33.

Adding to 12130332432513 its reverse (31523423303121), we get a palindrome (43653755735634).

The spelling of 12130332432513 in words is "twelve trillion, one hundred thirty billion, three hundred thirty-two million, four hundred thirty-two thousand, five hundred thirteen".

Divisors: 1 3 4043444144171 12130332432513