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121304010534257 is a prime number
BaseRepresentation
bin11011100101001101001010…
…011101010010110101110001
3120220111112212001122201220102
4123211031022131102311301
5111344421103144044012
61105554143152122145
734356632314635335
oct3345151235226561
9526445761581812
10121304010534257
1135718818615121
1211731643836355
13528bbc43935b5
1421d52071117c5
15e055e06d22c2
hex6e534a752d71

121304010534257 has 2 divisors, whose sum is σ = 121304010534258. Its totient is φ = 121304010534256.

The previous prime is 121304010534149. The next prime is 121304010534277. The reversal of 121304010534257 is 752435010403121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 72897426924001 + 48406583610256 = 8537999^2 + 6957484^2 .

It is a cyclic number.

It is not a de Polignac number, because 121304010534257 - 214 = 121304010517873 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 121304010534257.

It is not a weakly prime, because it can be changed into another prime (121304010534277) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60652005267128 + 60652005267129.

It is an arithmetic number, because the mean of its divisors is an integer number (60652005267129).

Almost surely, 2121304010534257 is an apocalyptic number.

It is an amenable number.

121304010534257 is a deficient number, since it is larger than the sum of its proper divisors (1).

121304010534257 is an equidigital number, since it uses as much as digits as its factorization.

121304010534257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 100800, while the sum is 38.

Adding to 121304010534257 its reverse (752435010403121), we get a palindrome (873739020937378).

The spelling of 121304010534257 in words is "one hundred twenty-one trillion, three hundred four billion, ten million, five hundred thirty-four thousand, two hundred fifty-seven".