1213055551131 has 4 divisors (see below), whose sum is σ = 1617407401512. Its totient is φ = 808703700752.

The previous prime is 1213055551129. The next prime is 1213055551157. The reversal of 1213055551131 is 1311555503121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1213055551131 - 2¹ = 1213055551129 is a prime.

It is a super-2 number, since 2×1213055551131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1213055551092 and 1213055551101.

It is not an unprimeable number, because it can be changed into a prime (1213055551531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 202175925186 + ... + 202175925191.

It is an arithmetic number, because the mean of its divisors is an integer number (404351850378).

Almost surely, 2^{1213055551131} is an apocalyptic number.

1213055551131 is a deficient number, since it is larger than the sum of its proper divisors (404351850381).

1213055551131 is an equidigital number, since it uses as much as digits as its factorization.

1213055551131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 404351850380.

The product of its (nonzero) digits is 11250, while the sum is 33.

The spelling of 1213055551131 in words is "one trillion, two hundred thirteen billion, fifty-five million, five hundred fifty-one thousand, one hundred thirty-one".