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121310035912147 is a prime number
BaseRepresentation
bin11011100101010010110001…
…100110010010010111010011
3120220112010101222110122111111
4123211102301212102113103
5111400020423143142042
61110001021112554151
734360234530541615
oct3345226146222723
9526463358418444
10121310035912147
113572032a7a9775
12117328456b2957
13528c6447a6564
1421d5619448db5
15e0584467e517
hex6e54b19925d3

121310035912147 has 2 divisors, whose sum is σ = 121310035912148. Its totient is φ = 121310035912146.

The previous prime is 121310035912129. The next prime is 121310035912189. The reversal of 121310035912147 is 741219530013121.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 121310035912147 - 223 = 121310027523539 is a prime.

It is a super-2 number, since 2×1213100359121472 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (121310035913147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60655017956073 + 60655017956074.

It is an arithmetic number, because the mean of its divisors is an integer number (60655017956074).

Almost surely, 2121310035912147 is an apocalyptic number.

121310035912147 is a deficient number, since it is larger than the sum of its proper divisors (1).

121310035912147 is an equidigital number, since it uses as much as digits as its factorization.

121310035912147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 45360, while the sum is 40.

Adding to 121310035912147 its reverse (741219530013121), we get a palindrome (862529565925268).

The spelling of 121310035912147 in words is "one hundred twenty-one trillion, three hundred ten billion, thirty-five million, nine hundred twelve thousand, one hundred forty-seven".