Base | Representation |
---|---|
bin | 10110100110001010… |
… | …00000110011101001 |
3 | 1011022110001220102101 |
4 | 23103011000303221 |
5 | 144321044204233 |
6 | 5323434333401 |
7 | 606423564061 |
oct | 132305006351 |
9 | 34273056371 |
10 | 12131241193 |
11 | 5165851075 |
12 | 242688a261 |
13 | 11b43c6236 |
14 | 8312223a1 |
15 | 4b0046c7d |
hex | 2d3140ce9 |
12131241193 has 2 divisors, whose sum is σ = 12131241194. Its totient is φ = 12131241192.
The previous prime is 12131241181. The next prime is 12131241211. The reversal of 12131241193 is 39114213121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9134007184 + 2997234009 = 95572^2 + 54747^2 .
It is an emirp because it is prime and its reverse (39114213121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12131241193 - 213 = 12131233001 is a prime.
It is not a weakly prime, because it can be changed into another prime (12131241173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6065620596 + 6065620597.
It is an arithmetic number, because the mean of its divisors is an integer number (6065620597).
Almost surely, 212131241193 is an apocalyptic number.
It is an amenable number.
12131241193 is a deficient number, since it is larger than the sum of its proper divisors (1).
12131241193 is an equidigital number, since it uses as much as digits as its factorization.
12131241193 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1296, while the sum is 28.
The spelling of 12131241193 in words is "twelve billion, one hundred thirty-one million, two hundred forty-one thousand, one hundred ninety-three".
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