Base | Representation |
---|---|
bin | 1011000010001000011001… |
… | …0101000001010011111011 |
3 | 1120221201212001201222121101 |
4 | 2300202012111001103323 |
5 | 3042224240233114433 |
6 | 41445003150352231 |
7 | 2361311316452641 |
oct | 260420625012373 |
9 | 46851761658541 |
10 | 12131241301243 |
11 | 39579154a9a29 |
12 | 143b1481bb677 |
13 | 69cc817b979c |
14 | 2dd225c89191 |
15 | 160864c2c07d |
hex | b08865414fb |
12131241301243 has 4 divisors (see below), whose sum is σ = 12131402402920. Its totient is φ = 12131080199568.
The previous prime is 12131241301181. The next prime is 12131241301259. The reversal of 12131241301243 is 34210314213121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12131241301243 - 217 = 12131241170171 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12131241341243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80437833 + ... + 80588506.
It is an arithmetic number, because the mean of its divisors is an integer number (3032850600730).
Almost surely, 212131241301243 is an apocalyptic number.
12131241301243 is a deficient number, since it is larger than the sum of its proper divisors (161101677).
12131241301243 is an equidigital number, since it uses as much as digits as its factorization.
12131241301243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 161101676.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 12131241301243 its reverse (34210314213121), we get a palindrome (46341555514364).
The spelling of 12131241301243 in words is "twelve trillion, one hundred thirty-one billion, two hundred forty-one million, three hundred one thousand, two hundred forty-three".
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