Search a number
-
+
12131251401 = 34043750467
BaseRepresentation
bin10110100110001010…
…00011010011001001
31011022110002102102110
423103011003103021
5144321100021101
65323434452533
7606423635613
oct132305032311
934273072373
1012131251401
115165858805
122426894149
1311b43caa89
14831225db3
154b0049cd6
hex2d31434c9

12131251401 has 4 divisors (see below), whose sum is σ = 16175001872. Its totient is φ = 8087500932.

The previous prime is 12131251393. The next prime is 12131251409. The reversal of 12131251401 is 10415213121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (12131251393) and next prime (12131251409).

It is not a de Polignac number, because 12131251401 - 23 = 12131251393 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12131251409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2021875231 + ... + 2021875236.

It is an arithmetic number, because the mean of its divisors is an integer number (4043750468).

Almost surely, 212131251401 is an apocalyptic number.

It is an amenable number.

12131251401 is a deficient number, since it is larger than the sum of its proper divisors (4043750471).

12131251401 is an equidigital number, since it uses as much as digits as its factorization.

12131251401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4043750470.

The product of its (nonzero) digits is 240, while the sum is 21.

Adding to 12131251401 its reverse (10415213121), we get a palindrome (22546464522).

The spelling of 12131251401 in words is "twelve billion, one hundred thirty-one million, two hundred fifty-one thousand, four hundred one".

Divisors: 1 3 4043750467 12131251401