Base | Representation |
---|---|
bin | 10001101001110100001… |
… | …111111000111111100011 |
3 | 11021222022012012010000100 |
4 | 101221310033320333203 |
5 | 124333443030201011 |
6 | 2325145453353443 |
7 | 153434343132546 |
oct | 21516417707743 |
9 | 4258265163010 |
10 | 1213131100131 |
11 | 428538974a65 |
12 | 177143198883 |
13 | 8a522b9bb42 |
14 | 42a0445c85d |
15 | 218528d6d56 |
hex | 11a743f8fe3 |
1213131100131 has 24 divisors (see below), whose sum is σ = 1769266437120. Its totient is φ = 800928662256.
The previous prime is 1213131100123. The next prime is 1213131100151. The reversal of 1213131100131 is 1310011313121.
1213131100131 is a `hidden beast` number, since 121 + 313 + 1 + 100 + 131 = 666.
It is not a de Polignac number, because 1213131100131 - 23 = 1213131100123 is a prime.
It is a super-2 number, since 2×12131311001312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1213131100121) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2702790 + ... + 3119508.
It is an arithmetic number, because the mean of its divisors is an integer number (73719434880).
Almost surely, 21213131100131 is an apocalyptic number.
1213131100131 is a deficient number, since it is larger than the sum of its proper divisors (556135336989).
1213131100131 is a wasteful number, since it uses less digits than its factorization.
1213131100131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 419855 (or 419852 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 18.
Adding to 1213131100131 its reverse (1310011313121), we get a palindrome (2523142413252).
The spelling of 1213131100131 in words is "one trillion, two hundred thirteen billion, one hundred thirty-one million, one hundred thousand, one hundred thirty-one".
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