Base | Representation |
---|---|
bin | 11011100101010110110010… |
… | …001101101101110001011010 |
3 | 120220112112112000122201011122 |
4 | 123211112302031231301122 |
5 | 111400103232322342242 |
6 | 1110003012230325242 |
7 | 34360446316163123 |
oct | 3345266215556132 |
9 | 526475460581148 |
10 | 121314341215322 |
11 | 35722139a59772 |
12 | 117336474b9822 |
13 | 528cb7c731828 |
14 | 21d590715304a |
15 | e059e760ead2 |
hex | 6e55b236dc5a |
121314341215322 has 4 divisors (see below), whose sum is σ = 181971511822986. Its totient is φ = 60657170607660.
The previous prime is 121314341215321. The next prime is 121314341215421. The reversal of 121314341215322 is 223512143413121.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 90468080583841 + 30846260631481 = 9511471^2 + 5553941^2 .
It is a super-2 number, since 2×1213143412153222 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (121314341215321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30328585303829 + ... + 30328585303832.
Almost surely, 2121314341215322 is an apocalyptic number.
121314341215322 is a deficient number, since it is larger than the sum of its proper divisors (60657170607664).
121314341215322 is an equidigital number, since it uses as much as digits as its factorization.
121314341215322 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60657170607663.
The product of its digits is 34560, while the sum is 35.
Adding to 121314341215322 its reverse (223512143413121), we get a palindrome (344826484628443).
The spelling of 121314341215322 in words is "one hundred twenty-one trillion, three hundred fourteen billion, three hundred forty-one million, two hundred fifteen thousand, three hundred twenty-two".
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