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121315201144051 = 196385010586529
BaseRepresentation
bin11011100101010111100101…
…011110000101010011110011
3120220112121201221202121121211
4123211113211132011103303
5111400112012443102201
61110003233425500551
734360506530356015
oct3345274536052363
9526477657677554
10121315201144051
1135722540401972
12117338474a1757
13528cc889380b5
1421d598943c1b5
15e05a47d73651
hex6e55e57854f3

121315201144051 has 4 divisors (see below), whose sum is σ = 127700211730600. Its totient is φ = 114930190557504.

The previous prime is 121315201144037. The next prime is 121315201144063. The reversal of 121315201144051 is 150441102513121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 121315201144051 - 215 = 121315201111283 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (121315201144451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3192505293246 + ... + 3192505293283.

It is an arithmetic number, because the mean of its divisors is an integer number (31925052932650).

Almost surely, 2121315201144051 is an apocalyptic number.

121315201144051 is a deficient number, since it is larger than the sum of its proper divisors (6385010586549).

121315201144051 is an equidigital number, since it uses as much as digits as its factorization.

121315201144051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6385010586548.

The product of its (nonzero) digits is 4800, while the sum is 31.

Adding to 121315201144051 its reverse (150441102513121), we get a palindrome (271756303657172).

The spelling of 121315201144051 in words is "one hundred twenty-one trillion, three hundred fifteen billion, two hundred one million, one hundred forty-four thousand, fifty-one".

Divisors: 1 19 6385010586529 121315201144051