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121320034041 = 340440011347
BaseRepresentation
bin111000011111100111…
…1001100111011111001
3102121011000001021210010
41300333033030323321
53441430412042131
6131422245212133
711523265163103
oct1607717147371
9377130037703
10121320034041
11474a6aa6248
121b619a01049
13b5958180bb
145c2c7a0573
153250d01b46
hex1c3f3ccef9

121320034041 has 4 divisors (see below), whose sum is σ = 161760045392. Its totient is φ = 80880022692.

The previous prime is 121320034039. The next prime is 121320034049. The reversal of 121320034041 is 140430023121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 121320034041 - 21 = 121320034039 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121320033999 and 121320034017.

It is not an unprimeable number, because it can be changed into a prime (121320034049) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20220005671 + ... + 20220005676.

It is an arithmetic number, because the mean of its divisors is an integer number (40440011348).

Almost surely, 2121320034041 is an apocalyptic number.

It is an amenable number.

121320034041 is a deficient number, since it is larger than the sum of its proper divisors (40440011351).

121320034041 is an equidigital number, since it uses as much as digits as its factorization.

121320034041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40440011350.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 121320034041 its reverse (140430023121), we get a palindrome (261750057162).

The spelling of 121320034041 in words is "one hundred twenty-one billion, three hundred twenty million, thirty-four thousand, forty-one".

Divisors: 1 3 40440011347 121320034041