12132023113 has 4 divisors (see below), whose sum is σ = 13865169280. Its totient is φ = 10398876948.

The previous prime is 12132023087. The next prime is 12132023131. The reversal of 12132023113 is 31132023121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31132023121 = 43669 ⋅712909.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12132023113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12132023153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 866573073 + ... + 866573086.

It is an arithmetic number, because the mean of its divisors is an integer number (3466292320).

Almost surely, 2^12132023113 is an apocalyptic number.

It is an amenable number.

12132023113 is a deficient number, since it is larger than the sum of its proper divisors (1733146167).

12132023113 is an equidigital number, since it uses as much as digits as its factorization.

12132023113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1733146166.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 12132023113 its reverse (31132023121), we get a palindrome (43264046234).

It can be divided in two parts, 12 and 132023113, that added together give a triangular number (132023125 = T₁₆₂₄₉).

The spelling of 12132023113 in words is "twelve billion, one hundred thirty-two million, twenty-three thousand, one hundred thirteen".