121320434113 has 2 divisors, whose sum is σ = 121320434114. Its totient is φ = 121320434112.

The previous prime is 121320434107. The next prime is 121320434141. The reversal of 121320434113 is 311434023121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 120552700849 + 767733264 = 347207^2 + 27708^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-121320434113 is a prime.

It is not a weakly prime, because it can be changed into another prime (121320434153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60660217056 + 60660217057.

It is an arithmetic number, because the mean of its divisors is an integer number (60660217057).

Almost surely, 2^121320434113 is an apocalyptic number.

It is an amenable number.

121320434113 is a deficient number, since it is larger than the sum of its proper divisors (1).

121320434113 is an equidigital number, since it uses as much as digits as its factorization.

121320434113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 121320434113 its reverse (311434023121), we get a palindrome (432754457234).

The spelling of 121320434113 in words is "one hundred twenty-one billion, three hundred twenty million, four hundred thirty-four thousand, one hundred thirteen".