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1213211111113 is a prime number
BaseRepresentation
bin10001101001111001000…
…001000110111011001001
311021222111202202002110001
4101221321001012323021
5124334124021023423
62325201432323001
7153436334202661
oct21517101067311
94258452662401
101213211111113
1142857a053441
12177165b43461
138a536634211
1442a10d291a1
152185993dcad
hex11a79046ec9

1213211111113 has 2 divisors, whose sum is σ = 1213211111114. Its totient is φ = 1213211111112.

The previous prime is 1213211111107. The next prime is 1213211111149. The reversal of 1213211111113 is 3111111123121.

It is a m-pointer prime, because the next prime (1213211111149) can be obtained adding 1213211111113 to its product of digits (36).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1170698032144 + 42513078969 = 1081988^2 + 206187^2 .

It is a cyclic number.

It is not a de Polignac number, because 1213211111113 - 229 = 1212674240201 is a prime.

It is not a weakly prime, because it can be changed into another prime (1213211111173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606605555556 + 606605555557.

It is an arithmetic number, because the mean of its divisors is an integer number (606605555557).

Almost surely, 21213211111113 is an apocalyptic number.

It is an amenable number.

1213211111113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213211111113 is an equidigital number, since it uses as much as digits as its factorization.

1213211111113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 36, while the sum is 19.

Adding to 1213211111113 its reverse (3111111123121), we get a palindrome (4324322234234).

The spelling of 1213211111113 in words is "one trillion, two hundred thirteen billion, two hundred eleven million, one hundred eleven thousand, one hundred thirteen".