Base | Representation |
---|---|
bin | 1011000010001011101101… |
… | …0100010101001110101011 |
3 | 1120221211011000120110122121 |
4 | 2300202323110111032223 |
5 | 3042233100330010011 |
6 | 41445231305132111 |
7 | 2361342333105223 |
oct | 260427324251653 |
9 | 46854130513577 |
10 | 12132130313131 |
11 | 39582313067a4 |
12 | 143b355a8a037 |
13 | 6a0093a3691a |
14 | 2dd2abd85083 |
15 | 1608b7cd7e71 |
hex | b08bb5153ab |
12132130313131 has 8 divisors (see below), whose sum is σ = 12163751424000. Its totient is φ = 12100537301160.
The previous prime is 12132130313099. The next prime is 12132130313137. The reversal of 12132130313131 is 13131303123121.
12132130313131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12132130313131 - 25 = 12132130313099 is a prime.
It is a super-3 number, since 3×121321303131313 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12132130313096 and 12132130313105.
It is not an unprimeable number, because it can be changed into a prime (12132130313137) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6159931 + ... + 7887268.
It is an arithmetic number, because the mean of its divisors is an integer number (1520468928000).
Almost surely, 212132130313131 is an apocalyptic number.
12132130313131 is a deficient number, since it is larger than the sum of its proper divisors (31621110869).
12132130313131 is a wasteful number, since it uses less digits than its factorization.
12132130313131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14049449.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 12132130313131 its reverse (13131303123121), we get a palindrome (25263433436252).
The spelling of 12132130313131 in words is "twelve trillion, one hundred thirty-two billion, one hundred thirty million, three hundred thirteen thousand, one hundred thirty-one".
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