Base | Representation |
---|---|
bin | 111000011111101010… |
… | …0001010010100011001 |
3 | 102121011002111100001021 |
4 | 1300333110022110121 |
5 | 3441431230142131 |
6 | 131422333122441 |
7 | 11523312216145 |
oct | 1607724122431 |
9 | 377132440037 |
10 | 121321334041 |
11 | 474a7803a26 |
12 | 1b61a329421 |
13 | b595b81a2b |
14 | 5c2ca1c225 |
15 | 3250eabe11 |
hex | 1c3f50a519 |
121321334041 has 2 divisors, whose sum is σ = 121321334042. Its totient is φ = 121321334040.
The previous prime is 121321334021. The next prime is 121321334047. The reversal of 121321334041 is 140433123121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 81783988441 + 39537345600 = 285979^2 + 198840^2 .
It is a cyclic number.
It is not a de Polignac number, because 121321334041 - 213 = 121321325849 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 121321333997 and 121321334015.
It is not a weakly prime, because it can be changed into another prime (121321334047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60660667020 + 60660667021.
It is an arithmetic number, because the mean of its divisors is an integer number (60660667021).
Almost surely, 2121321334041 is an apocalyptic number.
It is an amenable number.
121321334041 is a deficient number, since it is larger than the sum of its proper divisors (1).
121321334041 is an equidigital number, since it uses as much as digits as its factorization.
121321334041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 121321334041 its reverse (140433123121), we get a palindrome (261754457162).
The spelling of 121321334041 in words is "one hundred twenty-one billion, three hundred twenty-one million, three hundred thirty-four thousand, forty-one".
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