Base | Representation |
---|---|
bin | 10001101001111001101… |
… | …011011010111110101011 |
3 | 11021222112112121122002001 |
4 | 101221321223122332223 |
5 | 124334134341001212 |
6 | 2325202510151431 |
7 | 153436530401512 |
oct | 21517153327653 |
9 | 4258475548061 |
10 | 1213222203307 |
11 | 42858533a144 |
12 | 1771697b2577 |
13 | 8a538a18c4a |
14 | 42a125b5679 |
15 | 2185a8d0657 |
hex | 11a79adafab |
1213222203307 has 2 divisors, whose sum is σ = 1213222203308. Its totient is φ = 1213222203306.
The previous prime is 1213222203299. The next prime is 1213222203313. The reversal of 1213222203307 is 7033022223121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1213222203307 - 23 = 1213222203299 is a prime.
It is a super-2 number, since 2×12132222033072 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1213222203407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606611101653 + 606611101654.
It is an arithmetic number, because the mean of its divisors is an integer number (606611101654).
Almost surely, 21213222203307 is an apocalyptic number.
1213222203307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1213222203307 is an equidigital number, since it uses as much as digits as its factorization.
1213222203307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 28.
Adding to 1213222203307 its reverse (7033022223121), we get a palindrome (8246244426428).
The spelling of 1213222203307 in words is "one trillion, two hundred thirteen billion, two hundred twenty-two million, two hundred three thousand, three hundred seven".
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