12132411433 has 4 divisors (see below), whose sum is σ = 12132943108. Its totient is φ = 12131879760.

The previous prime is 12132411413. The next prime is 12132411463. The reversal of 12132411433 is 33411423121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7231291369 + 4901120064 = 85037^2 + 70008^2 .

It is a cyclic number.

It is not a de Polignac number, because 12132411433 - 2²¹ = 12130314281 is a prime.

It is a super-2 number, since 2×12132411433² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12132411398 and 12132411407.

It is not an unprimeable number, because it can be changed into a prime (12132411413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 229998 + ... + 277783.

It is an arithmetic number, because the mean of its divisors is an integer number (3033235777).

Almost surely, 2^12132411433 is an apocalyptic number.

It is an amenable number.

12132411433 is a deficient number, since it is larger than the sum of its proper divisors (531675).

12132411433 is an equidigital number, since it uses as much as digits as its factorization.

12132411433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 531674.

The product of its digits is 1728, while the sum is 25.

Adding to 12132411433 its reverse (33411423121), we get a palindrome (45543834554).

The spelling of 12132411433 in words is "twelve billion, one hundred thirty-two million, four hundred eleven thousand, four hundred thirty-three".