Base | Representation |
---|---|
bin | 10110100110010111… |
… | …11000111100001001 |
3 | 1011022120110111101011 |
4 | 23103023320330021 |
5 | 144322024401402 |
6 | 5323541123521 |
7 | 606445113025 |
oct | 132313707411 |
9 | 34276414334 |
10 | 12133043977 |
11 | 516687257a |
12 | 24273b95a1 |
13 | 11b48a7982 |
14 | 831571385 |
15 | 4b02a0ed7 |
hex | 2d32f8f09 |
12133043977 has 2 divisors, whose sum is σ = 12133043978. Its totient is φ = 12133043976.
The previous prime is 12133043969. The next prime is 12133044013. The reversal of 12133043977 is 77934033121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11462700096 + 670343881 = 107064^2 + 25891^2 .
It is a cyclic number.
It is not a de Polignac number, because 12133043977 - 23 = 12133043969 is a prime.
It is a super-2 number, since 2×121330439772 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12133043947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6066521988 + 6066521989.
It is an arithmetic number, because the mean of its divisors is an integer number (6066521989).
Almost surely, 212133043977 is an apocalyptic number.
It is an amenable number.
12133043977 is a deficient number, since it is larger than the sum of its proper divisors (1).
12133043977 is an equidigital number, since it uses as much as digits as its factorization.
12133043977 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 95256, while the sum is 40.
The spelling of 12133043977 in words is "twelve billion, one hundred thirty-three million, forty-three thousand, nine hundred seventy-seven".
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