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121331021212993 is a prime number
BaseRepresentation
bin11011100101100110010100…
…011010110110110101000001
3120220121010120111000101102011
4123211212110122312311001
5111400341412412303433
61110014411320452521
734361606545626004
oct3345462432666501
9526533514011364
10121331021212993
1135729219421909
121173692161a141
13529160a342937
1421d664a53353b
15e06171b763cd
hex6e59946b6d41

121331021212993 has 2 divisors, whose sum is σ = 121331021212994. Its totient is φ = 121331021212992.

The previous prime is 121331021212963. The next prime is 121331021213027. The reversal of 121331021212993 is 399212120133121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 98728527505729 + 22602493707264 = 9936223^2 + 4754208^2 .

It is an emirp because it is prime and its reverse (399212120133121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 121331021212993 - 213 = 121331021204801 is a prime.

It is not a weakly prime, because it can be changed into another prime (121331021212903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60665510606496 + 60665510606497.

It is an arithmetic number, because the mean of its divisors is an integer number (60665510606497).

Almost surely, 2121331021212993 is an apocalyptic number.

It is an amenable number.

121331021212993 is a deficient number, since it is larger than the sum of its proper divisors (1).

121331021212993 is an equidigital number, since it uses as much as digits as its factorization.

121331021212993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34992, while the sum is 40.

The spelling of 121331021212993 in words is "one hundred twenty-one trillion, three hundred thirty-one billion, twenty-one million, two hundred twelve thousand, nine hundred ninety-three".