Search a number
-
+
1213315144403 = 1758169012863
BaseRepresentation
bin10001101001111111001…
…101111101101011010011
311021222210000111112021212
4101221333031331223103
5124334332134110103
62325220030210335
7153442036364015
oct21517715755323
94258700445255
101213315144403
1142862284a16a
121771949539ab
138a55205a78b
1442a20a8a1b5
1521863b3d7d8
hex11a7f37dad3

1213315144403 has 4 divisors (see below), whose sum is σ = 1213384174848. Its totient is φ = 1213246113960.

The previous prime is 1213315144313. The next prime is 1213315144439. The reversal of 1213315144403 is 3044415133121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1213315144403 - 28 = 1213315144147 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1213315144403.

It is not an unprimeable number, because it can be changed into a prime (1213315144463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34488851 + ... + 34524012.

It is an arithmetic number, because the mean of its divisors is an integer number (303346043712).

Almost surely, 21213315144403 is an apocalyptic number.

1213315144403 is a deficient number, since it is larger than the sum of its proper divisors (69030445).

1213315144403 is an equidigital number, since it uses as much as digits as its factorization.

1213315144403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 69030444.

The product of its (nonzero) digits is 17280, while the sum is 32.

The spelling of 1213315144403 in words is "one trillion, two hundred thirteen billion, three hundred fifteen million, one hundred forty-four thousand, four hundred three".

Divisors: 1 17581 69012863 1213315144403