1213401400033 has 4 divisors (see below), whose sum is σ = 1213449727428. Its totient is φ = 1213353072640.

The previous prime is 1213401399989. The next prime is 1213401400037. The reversal of 1213401400033 is 3300041043121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 840021741729 + 373379658304 = 916527^2 + 611048^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1213401400033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1213401399977 and 1213401400013.

It is not an unprimeable number, because it can be changed into a prime (1213401400037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24126016 + ... + 24176257.

It is an arithmetic number, because the mean of its divisors is an integer number (303362431857).

Almost surely, 2^{1213401400033} is an apocalyptic number.

It is an amenable number.

1213401400033 is a deficient number, since it is larger than the sum of its proper divisors (48327395).

1213401400033 is an equidigital number, since it uses as much as digits as its factorization.

1213401400033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48327394.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 1213401400033 its reverse (3300041043121), we get a palindrome (4513442443154).

The spelling of 1213401400033 in words is "one trillion, two hundred thirteen billion, four hundred one million, four hundred thousand, thirty-three".