Base | Representation |
---|---|
bin | 111000100000001110… |
… | …0100001111010001001 |
3 | 102121012102012011100121 |
4 | 1301000130201322021 |
5 | 3442001104230113 |
6 | 131424251503241 |
7 | 11523632401153 |
oct | 1610034417211 |
9 | 377172164317 |
10 | 121340305033 |
11 | 47507491132 |
12 | 1b624757b21 |
13 | b599a9497c |
14 | 5c31359ad3 |
15 | 32529a7e8d |
hex | 1c40721e89 |
121340305033 has 2 divisors, whose sum is σ = 121340305034. Its totient is φ = 121340305032.
The previous prime is 121340304989. The next prime is 121340305057. The reversal of 121340305033 is 330503043121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 74187051129 + 47153253904 = 272373^2 + 217148^2 .
It is a cyclic number.
It is not a de Polignac number, because 121340305033 - 229 = 120803434121 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 121340304989 and 121340305007.
It is not a weakly prime, because it can be changed into another prime (121340345033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60670152516 + 60670152517.
It is an arithmetic number, because the mean of its divisors is an integer number (60670152517).
Almost surely, 2121340305033 is an apocalyptic number.
It is an amenable number.
121340305033 is a deficient number, since it is larger than the sum of its proper divisors (1).
121340305033 is an equidigital number, since it uses as much as digits as its factorization.
121340305033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3240, while the sum is 25.
Adding to 121340305033 its reverse (330503043121), we get a palindrome (451843348154).
The spelling of 121340305033 in words is "one hundred twenty-one billion, three hundred forty million, three hundred five thousand, thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •