Search a number
-
+
1213412542481 is a prime number
BaseRepresentation
bin10001101010000101000…
…001100000100000010001
311022000000210202212100002
4101222011001200200101
5124340032102324411
62325233425535345
7153444331301306
oct21520501404021
94260023685302
101213412542481
11428672823847
121772014a4555
138a56929cb89
1442a2d9a10ad
152186c47c33b
hex11a85060811

1213412542481 has 2 divisors, whose sum is σ = 1213412542482. Its totient is φ = 1213412542480.

The previous prime is 1213412542451. The next prime is 1213412542567. The reversal of 1213412542481 is 1842452143121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1201435210000 + 11977332481 = 1096100^2 + 109441^2 .

It is an emirp because it is prime and its reverse (1842452143121) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1213412542481 is a prime.

It is a super-2 number, since 2×12134125424812 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1213412542451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606706271240 + 606706271241.

It is an arithmetic number, because the mean of its divisors is an integer number (606706271241).

Almost surely, 21213412542481 is an apocalyptic number.

It is an amenable number.

1213412542481 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213412542481 is an equidigital number, since it uses as much as digits as its factorization.

1213412542481 is an evil number, because the sum of its binary digits is even.

The product of its digits is 61440, while the sum is 38.

The spelling of 1213412542481 in words is "one trillion, two hundred thirteen billion, four hundred twelve million, five hundred forty-two thousand, four hundred eighty-one".