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12134143032331 is a prime number
BaseRepresentation
bin1011000010010011001101…
…0010001111110000001011
31120222000100021212012100011
42300210303102033300023
53042301211104013311
641450203124452351
72361443242663225
oct260446322176013
946860307765304
1012134143032331
1139590744504a1
12143b817b4a0b7
136a0324a15428
142dd41d3d1415
1516098485e321
hexb093348fc0b

12134143032331 has 2 divisors, whose sum is σ = 12134143032332. Its totient is φ = 12134143032330.

The previous prime is 12134143032311. The next prime is 12134143032343. The reversal of 12134143032331 is 13323034143121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12134143032331 - 217 = 12134142901259 is a prime.

It is a super-2 number, since 2×121341430323312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12134143032293 and 12134143032302.

It is not a weakly prime, because it can be changed into another prime (12134143032311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6067071516165 + 6067071516166.

It is an arithmetic number, because the mean of its divisors is an integer number (6067071516166).

Almost surely, 212134143032331 is an apocalyptic number.

12134143032331 is a deficient number, since it is larger than the sum of its proper divisors (1).

12134143032331 is an equidigital number, since it uses as much as digits as its factorization.

12134143032331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 12134143032331 its reverse (13323034143121), we get a palindrome (25457177175452).

The spelling of 12134143032331 in words is "twelve trillion, one hundred thirty-four billion, one hundred forty-three million, thirty-two thousand, three hundred thirty-one".