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1213433042057 is a prime number
BaseRepresentation
bin10001101010000110001…
…111101101010010001001
311022000002020100100110122
4101222012033231102021
5124340102324321212
62325235441153025
7153445000450655
oct21520617552211
94260066310418
101213433042057
11428683355445
1217720832b775
138a5705c97c2
1442a325b9a65
152186e17b272
hex11a863ed489

1213433042057 has 2 divisors, whose sum is σ = 1213433042058. Its totient is φ = 1213433042056.

The previous prime is 1213433042009. The next prime is 1213433042083. The reversal of 1213433042057 is 7502403343121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1052452343881 + 160980698176 = 1025891^2 + 401224^2 .

It is a cyclic number.

It is not a de Polignac number, because 1213433042057 - 222 = 1213428847753 is a prime.

It is not a weakly prime, because it can be changed into another prime (1213433042557) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606716521028 + 606716521029.

It is an arithmetic number, because the mean of its divisors is an integer number (606716521029).

Almost surely, 21213433042057 is an apocalyptic number.

It is an amenable number.

1213433042057 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213433042057 is an equidigital number, since it uses as much as digits as its factorization.

1213433042057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60480, while the sum is 35.

Adding to 1213433042057 its reverse (7502403343121), we get a palindrome (8715836385178).

The spelling of 1213433042057 in words is "one trillion, two hundred thirteen billion, four hundred thirty-three million, forty-two thousand, fifty-seven".