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1213433093857 is a prime number
BaseRepresentation
bin10001101010000110001…
…111111001111011100001
311022000002020102222112011
4101222012033321323201
5124340102333000412
62325235442232521
7153445001054665
oct21520617717341
94260066388464
101213433093857
11428683390356
12177208355741
138a57061725a
1442a325d08a5
152186e18b7a7
hex11a863f9ee1

1213433093857 has 2 divisors, whose sum is σ = 1213433093858. Its totient is φ = 1213433093856.

The previous prime is 1213433093849. The next prime is 1213433093921. The reversal of 1213433093857 is 7583903343121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 958174730496 + 255258363361 = 978864^2 + 505231^2 .

It is a cyclic number.

It is not a de Polignac number, because 1213433093857 - 23 = 1213433093849 is a prime.

It is a super-2 number, since 2×12134330938572 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1213433093857.

It is not a weakly prime, because it can be changed into another prime (1213433043857) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606716546928 + 606716546929.

It is an arithmetic number, because the mean of its divisors is an integer number (606716546929).

Almost surely, 21213433093857 is an apocalyptic number.

It is an amenable number.

1213433093857 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213433093857 is an equidigital number, since it uses as much as digits as its factorization.

1213433093857 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1632960, while the sum is 49.

The spelling of 1213433093857 in words is "one trillion, two hundred thirteen billion, four hundred thirty-three million, ninety-three thousand, eight hundred fifty-seven".