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1213443114617 is a prime number
BaseRepresentation
bin10001101010000110110…
…110001000011001111001
311022000002221022002102102
4101222012312020121321
5124340112414131432
62325240441113145
7153445152202016
oct21520666103171
94260087262372
101213443114617
11428689005078
1217720b7887b5
138a5727153b6
1442a33a7c70d
152186eeba962
hex11a86d88679

1213443114617 has 2 divisors, whose sum is σ = 1213443114618. Its totient is φ = 1213443114616.

The previous prime is 1213443114613. The next prime is 1213443114677. The reversal of 1213443114617 is 7164113443121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 855882169321 + 357560945296 = 925139^2 + 597964^2 .

It is a cyclic number.

It is not a de Polignac number, because 1213443114617 - 22 = 1213443114613 is a prime.

It is a super-2 number, since 2×12134431146172 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1213443114613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606721557308 + 606721557309.

It is an arithmetic number, because the mean of its divisors is an integer number (606721557309).

Almost surely, 21213443114617 is an apocalyptic number.

It is an amenable number.

1213443114617 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213443114617 is an equidigital number, since it uses as much as digits as its factorization.

1213443114617 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 48384, while the sum is 38.

Adding to 1213443114617 its reverse (7164113443121), we get a palindrome (8377556557738).

The spelling of 1213443114617 in words is "one trillion, two hundred thirteen billion, four hundred forty-three million, one hundred fourteen thousand, six hundred seventeen".