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121345043537 is a prime number
BaseRepresentation
bin111000100000010111…
…0100110110001010001
3102121012202002220100202
41301000232212301101
53442003312343122
6131424541224545
711524020565064
oct1610056466121
9377182086322
10121345043537
114750a128253
121b626262155
13b59aa63713
145c31c308db
1532530e1e92
hex1c40ba6c51

121345043537 has 2 divisors, whose sum is σ = 121345043538. Its totient is φ = 121345043536.

The previous prime is 121345043497. The next prime is 121345043593. The reversal of 121345043537 is 735340543121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 121310103616 + 34939921 = 348296^2 + 5911^2 .

It is a cyclic number.

It is not a de Polignac number, because 121345043537 - 210 = 121345042513 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 121345043537.

It is not a weakly prime, because it can be changed into another prime (121345042537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60672521768 + 60672521769.

It is an arithmetic number, because the mean of its divisors is an integer number (60672521769).

Almost surely, 2121345043537 is an apocalyptic number.

It is an amenable number.

121345043537 is a deficient number, since it is larger than the sum of its proper divisors (1).

121345043537 is an equidigital number, since it uses as much as digits as its factorization.

121345043537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 151200, while the sum is 38.

Adding to 121345043537 its reverse (735340543121), we get a palindrome (856685586658).

The spelling of 121345043537 in words is "one hundred twenty-one billion, three hundred forty-five million, forty-three thousand, five hundred thirty-seven".